1652. Defuse the Bomb

Description

You have a bomb to defuse, and your time is running out! Your informer will provide you with a circular array code of length of n and a key k.

To decrypt the code, you must replace every number. All the numbers are replaced simultaneously.

  • If k > 0, replace the ith number with the sum of the next k numbers.
  • If k < 0, replace the ith number with the sum of the previous k numbers.
  • If k == 0, replace the ith number with 0.

As code is circular, the next element of code[n-1] is code[0], and the previous element of code[0] is code[n-1].

Given the circular array code and an integer key k, return the decrypted code to defuse the bomb!

 

Example 1:

Input: code = [5,7,1,4], k = 3
Output: [12,10,16,13]
Explanation: Each number is replaced by the sum of the next 3 numbers. The decrypted code is [7+1+4, 1+4+5, 4+5+7, 5+7+1]. Notice that the numbers wrap around.

Example 2:

Input: code = [1,2,3,4], k = 0
Output: [0,0,0,0]
Explanation: When k is zero, the numbers are replaced by 0. 

Example 3:

Input: code = [2,4,9,3], k = -2
Output: [12,5,6,13]
Explanation: The decrypted code is [3+9, 2+3, 4+2, 9+4]. Notice that the numbers wrap around again. If k is negative, the sum is of the previous numbers.

 

Constraints:

  • n == code.length
  • 1 <= n <= 100
  • 1 <= code[i] <= 100
  • -(n - 1) <= k <= n - 1

Solutions

Solution 1

Python Code
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class Solution:
    def decrypt(self, code: List[int], k: int) -> List[int]:
        n = len(code)
        ans = [0] * n
        if k == 0:
            return ans
        for i in range(n):
            if k > 0:
                for j in range(i + 1, i + k + 1):
                    ans[i] += code[j % n]
            else:
                for j in range(i + k, i):
                    ans[i] += code[(j + n) % n]
        return ans

Java Code
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class Solution {
    public int[] decrypt(int[] code, int k) {
        int n = code.length;
        int[] ans = new int[n];
        if (k == 0) {
            return ans;
        }
        for (int i = 0; i < n; ++i) {
            if (k > 0) {
                for (int j = i + 1; j < i + k + 1; ++j) {
                    ans[i] += code[j % n];
                }
            } else {
                for (int j = i + k; j < i; ++j) {
                    ans[i] += code[(j + n) % n];
                }
            }
        }
        return ans;
    }
}

C++ Code
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class Solution {
public:
    vector<int> decrypt(vector<int>& code, int k) {
        int n = code.size();
        vector<int> ans(n);
        if (k == 0) {
            return ans;
        }
        for (int i = 0; i < n; ++i) {
            if (k > 0) {
                for (int j = i + 1; j < i + k + 1; ++j) {
                    ans[i] += code[j % n];
                }
            } else {
                for (int j = i + k; j < i; ++j) {
                    ans[i] += code[(j + n) % n];
                }
            }
        }
        return ans;
    }
};

Go Code
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func decrypt(code []int, k int) []int {
	n := len(code)
	ans := make([]int, n)
	if k == 0 {
		return ans
	}
	for i := 0; i < n; i++ {
		if k > 0 {
			for j := i + 1; j < i+k+1; j++ {
				ans[i] += code[j%n]
			}
		} else {
			for j := i + k; j < i; j++ {
				ans[i] += code[(j+n)%n]
			}
		}
	}
	return ans
}

TypeScript Code
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function decrypt(code: number[], k: number): number[] {
    const n = code.length;
    if (k === 0) {
        return code.fill(0);
    }
    const isPrefix = k < 0;
    if (isPrefix) {
        k *= -1;
    }
    const map = new Map<number, [number, number]>();
    let prefix = 0;
    let suffix = 0;
    for (let i = 1; i <= k; i++) {
        prefix += code[n - i];
        suffix += code[i];
    }
    map.set(0, [prefix, suffix]);

    for (let i = 1; i < n; i++) {
        let [p, s] = map.get(i - 1);
        p -= code[n - k - 1 + i] ?? code[i - k - 1];
        p += code[i - 1];
        s -= code[i];
        s += code[i + k] ?? code[i + k - n];
        map.set(i, [p, s]);
    }
    for (let i = 0; i < n; i++) {
        code[i] = map.get(i)[Number(!isPrefix)];
    }
    return code;
}

Solution 2

Python Code
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class Solution:
    def decrypt(self, code: List[int], k: int) -> List[int]:
        n = len(code)
        ans = [0] * n
        if k == 0:
            return ans
        s = list(accumulate(code + code, initial=0))
        for i in range(n):
            if k > 0:
                ans[i] = s[i + k + 1] - s[i + 1]
            else:
                ans[i] = s[i + n] - s[i + k + n]
        return ans

Java Code
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class Solution {
    public int[] decrypt(int[] code, int k) {
        int n = code.length;
        int[] ans = new int[n];
        if (k == 0) {
            return ans;
        }
        int[] s = new int[n << 1 | 1];
        for (int i = 0; i < n << 1; ++i) {
            s[i + 1] = s[i] + code[i % n];
        }
        for (int i = 0; i < n; ++i) {
            if (k > 0) {
                ans[i] = s[i + k + 1] - s[i + 1];
            } else {
                ans[i] = s[i + n] - s[i + k + n];
            }
        }
        return ans;
    }
}

C++ Code
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class Solution {
public:
    vector<int> decrypt(vector<int>& code, int k) {
        int n = code.size();
        vector<int> ans(n);
        if (k == 0) {
            return ans;
        }
        vector<int> s(n << 1 | 1);
        for (int i = 0; i < n << 1; ++i) {
            s[i + 1] = s[i] + code[i % n];
        }
        for (int i = 0; i < n; ++i) {
            if (k > 0) {
                ans[i] = s[i + k + 1] - s[i + 1];
            } else {
                ans[i] = s[i + n] - s[i + k + n];
            }
        }
        return ans;
    }
};

Go Code
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func decrypt(code []int, k int) []int {
	n := len(code)
	ans := make([]int, n)
	if k == 0 {
		return ans
	}
	s := make([]int, n<<1|1)
	for i := 0; i < n<<1; i++ {
		s[i+1] = s[i] + code[i%n]
	}
	for i := range code {
		if k > 0 {
			ans[i] = s[i+k+1] - s[i+1]
		} else {
			ans[i] = s[i+n] - s[i+k+n]
		}
	}
	return ans
}